Q:

Phyllis invested a total of 70000 dollars, spread across two accounts. One account has a simple interest rate of 5 percent per year. The second account has a rate of 6 percent per year. After one year, the total interest earned on these investments was 3870 dollars. How much money did she invest at each rate?

Accepted Solution

A:
Answer:$33,000 invested in 5% account$37,000 invested in 6% accountStep-by-step explanation:Let amount invested in 5% be xand amount invested in 6% be yWe can write:0.05x + 0.06y = 3870andx + y = 70,000 Β [or x = 70,000 - y]Replacing 2nd in 1st we get and solve:0.05(70,000 - y) + 0.06y = 38703500 - 0.05y + 0.06y = 38700.01y = 370y = 37,000and x = 70,000 - 37,000 = 33,000Thus,$33,000 invested in 5% account$37,000 invested in 6% account