HELP!!Write the equation -4x^2+9y^2+32x-64=0 in standard form. Show each step of the process.
Accepted Solution
A:
Our equation is -4x∧2 +9y∧2 +32x- 64 =0, to write it in standard form we start by re-arranging it: -4x∧2 + 32x + 9y∧2- 64= 0 taking 64 to the other side, -4x∧2 + 32x + 9y∧2 = 64 simplifying, -4(x∧2 + 8x) + 9 (y∧2 +0) = 64 we add the square of half the coefficient of x and -4(x∧2 + 8x + 16) + 9 (y∧2 + 0) = 64 then we have -4 (x + 4)∧2 + 9 (y+0)∧2 = 64 , by so doing we have written the equation in the standard form.