Q:

For a sample of eight​ bears, researchers measured the distances around the​ bears' chests and weighed the bears. Minitab was used to find that the value of the linear correlation coefficient is requals0.952. Using alphaequals​0.05, determine if there is a linear correlation between chest size and weight. What proportion of the variation in weight can be explained by the linear relationship between weight and chest​ size?

Accepted Solution

A:
Answer:Step-by-step explanation:Given that for a sample of eight​ bears, researchers measured the distances around the​ bears' chests and weighed the bears. r = linear correlation coeff = 0.952H_0: r =0\\ H_1 :r\neq 0(Two tailed test)r difference = 0.952n=8Std error = \sqrt{\frac{1-r^2}{n-2} } =0.12496Test statistic t = 0.952/0.12496 = 7.618Alpha = 0.05df = 6p value = 0.000267This implies H0 is rejected.There exists a linear relation between the variables and r cannot be 00.952^2 = 0.906=90.6% of variation in weight can be explained by the linear relationship between weight and chest​ size